determine the value (s) of m for which the equation x^2+m(4x+m-1)+2=0 has real roots
Answers
Answered by
4
Answer:
m >= 2/3 for equation to have real roots
Explanation:
For real roots Discriminant, D >= 0
Now
12m - 8 >= 0 and m+1 >= 0
m >= 8/12 m >= -1
m >= 2/3
Hence taking common from both the equation we can say that m>= 2/3 so that equation has real roots.
Similar questions