Determine the values of all four Quantum numbers of the 8th electron in the oxygen atom and 15th electron in the chlorine atom and the last electron in the chromium atom
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For 8th electron of oxygen, n=2, l=1, m= +1 or -1 , s = +1/2 or -1/2 For 15th electron of chlorine, n=3, l=1, m= 0, s = +1/2 or -1/2 For last electron of chromium, n=4, l=0, m= 0, s = +1/2 or -1/2
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