Question

Determine the values of m for which the quadratic equation mx² + 6x + 2 = 0 has both roots real.

Answer 1

Answer:

b2-4ac=0

so,

36-4×m×2=0

36-8m=0

m=36/8

m=9/2 that's a answer pls follow me

and make this answer brainlist

Answer 2

Answer:

9 / 2

Step-by-step explanation:

Given :

p ( x ) = m x² + 6 x + 2 = 0

Since p ( x ) has equal and real roots :

= > D = 0

= > b² - 4 a c = 0

Putting values here we get :

= > 6² - 4 × m × 2 = 0

= > 36 - 8 m = 0

= > 8 m = 36

= > m = 9 / 2

Therefore , value of m is 9 / 2.

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