Determine the values of p for which the quadratic equation: 2×2 + p x + 8 = 0 has real roots.
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Hey
Here is your answer,
2x^2 +px+8=0
b^2-4ac=0
(P)^2 - 4x2x8=0
P^2-64=0
P^2=64
P=8
Hope it helps you!
Here is your answer,
2x^2 +px+8=0
b^2-4ac=0
(P)^2 - 4x2x8=0
P^2-64=0
P^2=64
P=8
Hope it helps you!
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