Determine the van hoff factor when 80% of k2so4 is dissociated
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Answer:
van't Hoff factor = i = 2
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Answer:
i = 2.6
Explanation:
K₂SO₄ => 2K⁺ + SO4²⁻ ; n = 3
degree of dissociation = (i-1)/(n-1)
⇒ 80% = (i-1)/(3-1)
⇒ 0.8 x 2 = i - 1
⇒ 1.6 + 1 = i
⇒ i = 2.6
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