Question

Determine the vapour density of the gas so2(s=32,o=16)

Answer 1

Answer:

Molar mass =2*vapour density

Explanation:

Vapour density =32+32/2

=32

Answer 2

Answer:

The vapor density of the gas $\left(\mathrm{SO}_{2}\right)$ is 32.035

Explanation:

The weight of a vapor or gas corresponded to the weight of an equal volume of air; an expression of the density of the vapor or gas. Materials lighter than air include vapor densities less than 1.0 (example: acetylene, methane, hydrogen).

Vapor density exists as the density of vapor in relation to that of hydrogen. It may be described as the mass of a certain volume of a substance divided by the mass of the identical volume of hydrogen.

Vapor density of Sulphur dioxide $\left(\mathrm{SO}_{2}\right)$

To calculate the vapor density of the given substance, the following formula must be used

Vapor density$=\frac{\text { Molecularweight }}{2}$

The molecular weight of $\mathrm{SO}_{2}$ is $64.07 \mathrm{~g} / \mathrm{mol}$.

When this existed substituted in the vapor density formula it provides

Vapor density of $S O_{2}=\frac{64.07}{2}=32.035$

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