Question

Determine the vertices of the triangle formed by the lines represented by the equation 4x-5y-20=0 and 3x+5y-15=0 and y-axis. Also find the area of the triangle so formed?
IT'S URGENT... plz solve it fastly ​

Answer 1

Answer:

Step-by-step explanation:

Given:

$4x - 5y - 20 = 0 \\ 3x + 5y - 15 = 0$

To find:Find the vertices of the triangle formed by the lines represented by the equation 4x-5y-20=0 and 3x+5y-15=0 and y-axis. Also find the area of the triangle so formed?

Solution:

Draw the graph of both equations.

Step 1: Find two points for eq1

put x=0

$4(0) - 5y - 20 = 0 \\ \\ - 5y = 20 \\ \\ y = - 4$

One point is (0,-4)

put y=0

$4x - 5(0) - 20 = 0 \\ \\ 4x = 20 \\ \\ x = 5$

Another point is (5,0)

Mark these points on graph and draw line 1.

Step 2:Find two points for eq2

Put x=0

$3(0) + 5y - 15 = 0 \\ \\ + 5y =15 \\ \\y = 3$

First point is (0,3)

put y=0

$3 x + 5(0) - 15 = 0 \\ \\ 3x = 15 \\ \\ x = 5$

point is (5,0)

Mark these points on graph and draw line.

graph is attached.

Step 3: Triangle formed by lines and y-axis is shown and vertices of triangle are

A (0,3), B(0,-4) and C(5,0)

Step 4: Area of triangle

$ar(∆ABC)=\frac{1}{2} \times Base \times height$

Base:AB=7 units

Height:OC: 5 units

$ar(∆ABC) = \frac{1}{2} \times 7 \times 5 \\ \\ ar(∆ABC) = \frac{35}{2} \: {unit}^{2}$

Hope it helps you.

To learn more on brainly:

Solve the following pair of linear equations graphically. Also write the observations.

(i) x + y = 1 ; 2x - 3y = 7

https://brainly.in/question/41675964