Question

determine the voltage drop across the 10 Ω resistance in the circuit?​

Answer 1

Answer:

Now, i1 = V(supply) / R(equivalent) = 5 /22 = 0.227 amps. ...

Voltage drop across 10 ohm -> Vr1 = 10 * i1 = 10 × 0.227 volts. ...

Now, i2 = i1 * (R3/(R1+R2)) ...

Voltage drop across 20 ohm -> Vr2 = 20 * i2 = 20 × 0.1362 volts. ...

Now, i3 = i1 * (R2/(R1+R2))

Step-by-step explanation:

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Answer 2

ANSWER-

Answer: ...

Now, i1 = V(supply) / R(equivalent) = 5 /22 = 0.227 amps. ...

Voltage drop across 10 ohm -> Vr1 = 10 * i1 = 10 × 0.227 volts. ...

Now, i2 = i1 * (R3/(R1+R2)) ...

Voltage drop across 20 ohm -> Vr2 = 20 * i2 = 20 × 0.1362 volts. ...

Now, i3 = i1 * (R2/(R1+R2))

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