Determine the volume in liters occupied by 16.3 g of carbon dioxide at STP
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Answer:-
Required volume of carbon dioxide is
8.3 L .
Explanation:-
Method (1) :-
Molar mass of CO₂ :-
= 12+32 = 44g/mol
We know that at STP , 1 mole of any ideal gas occupies a volume of 22.4 L.
∵ 44g of CO₂ occupies a volume of 22.4L
∴ 16.3g of CO₂ will occupy a volume of :-
= 16.3×22.4/44
= 365.12/44
= 8.3 L
Method (2) :-
According to Ideal gas equation, we know that :-
PV = nRT
Where :-
• P is the pressure.
• V is volume of the gas
• n is the number of moles of the gas.
• R is Ideal Gas Constant [0.082]
• T is temperature.
We know that at STP:-
• T = 273 K
• P = 1 atm
=> 1 × V = 16.3/44 × 0.082 × 273
=> V = 0.37 × 22.386
=> V = 8.3 L
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