Question

Determine the volume (in m) of diluted nitric acid 20% w/v HNO3 that can be prepared by
diluting 50 mL of conc. HNO3 with water 69.8% w /v

Answer 1

Explanation:

50ml of 20% w/v solution contains

$= 50 \times \frac{20}{100} = \frac{50}{5} = 10g \:$HNO3.

Let V ml be the volume of the solution after dilution.

Thus, V ml of 69.8% w/v solution contains

$v \: \times \frac{698}{100} = 10g$ HNO3.

V =

$\frac{10g \times 100 \: ml}{698g} \\ = 1.432ml \:$ HNO3.

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