Determine the volume of a conical vessel having radius of the base as 5cm and its slant height as 13 cm. ( use π = 3.14)
Answers
Answered by
11
slant height = √13² - 5² =12 cm
volume = 1/3
r²h
= 1/3 x22/7 x5x5x12
= 3.14.28 cm³
volume = 1/3
= 1/3 x22/7 x5x5x12
= 3.14.28 cm³
Answered by
11
Hey There !!
Given that -
Slant height , l = 13 cm
base radius , r = 5 cm
We know by Pythagoras theorem
a² +b² = c²
= l² = r² + h²
= h =√13 ² - 5²
= h = √ 169 - 25
h = √144 = 12 cm
Hence the height of that article is 12 cm
we know
volume of cone = 1/3 πrh
= 1/3× 3.14× 5× 12
= 3.14/3× 60
=62.8 cm³
hope this would help you !!
Given that -
Slant height , l = 13 cm
base radius , r = 5 cm
We know by Pythagoras theorem
a² +b² = c²
= l² = r² + h²
= h =√13 ² - 5²
= h = √ 169 - 25
h = √144 = 12 cm
Hence the height of that article is 12 cm
we know
volume of cone = 1/3 πrh
= 1/3× 3.14× 5× 12
= 3.14/3× 60
=62.8 cm³
hope this would help you !!
Similar questions