Determine the volume of diluted nitric acid (d = 1.11 gml1, 19% w/v hno3) that can be prepared by diluting with water 50 ml of conc. Hno3 (d = 1.42 g ml1, 69.8 % w/v).
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Answer:
Explanation:
1:d=m/v
M=19g
When v be 100ml
For conc. Hno3
M=69.8
V=50ml
Hence,as we know
M1v1=M2v2
Therefore,19×v1=69.8×50
V1=69.8×50/19
=3490/19
=183.68ml
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