Determine the volume of occupied by 5 grams of carbon dioxide gas at stp
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Answer:
2.464
Explanation:
1 mol occupies 22.4 lit
44 grams = 1 mol
5 gram= weight / molecular mass = 5 / 44= 0.11 mol
0.11 mol contains = 22.4 × 0.11 = 2.464
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