Question

Determine the volume of Oxygen consume for the combustion 96g of methane​

Answer 1

The reaction is:

CH4 + 2O2 ===> CO2 + 2H2O


Molar mass of CH4 (methane) =( 12 + 4(1) ) g = 16g.

Mass of methan used = 96g.

Moles of methan used = 96g / 16g = 6

From the reaction we get that,

For 1 moles CH4, 2 volumes of Oxygen is being used,
So for 16 moles we'll have to used 16×2 volumes i.e 32 volumes of oxygen.