Determine the volume of Oxygen consume for the combustion 96g of methane
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The reaction is:
CH4 + 2O2 ===> CO2 + 2H2O
Molar mass of CH4 (methane) =( 12 + 4(1) ) g = 16g.
Mass of methan used = 96g.
Moles of methan used = 96g / 16g = 6
From the reaction we get that,
For 1 moles CH4, 2 volumes of Oxygen is being used,
So for 16 moles we'll have to used 16×2 volumes i.e 32 volumes of oxygen.
CH4 + 2O2 ===> CO2 + 2H2O
Molar mass of CH4 (methane) =( 12 + 4(1) ) g = 16g.
Mass of methan used = 96g.
Moles of methan used = 96g / 16g = 6
From the reaction we get that,
For 1 moles CH4, 2 volumes of Oxygen is being used,
So for 16 moles we'll have to used 16×2 volumes i.e 32 volumes of oxygen.
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