Question

Determine the volumetrically the molarity of HCL Solution with the help of m/20 NAOH solution supplied

Answer 1

$0.05M HCl$

Explanation:

   *  The chemical reaction for the reaction in between $HCl$ and $NaOH$ is

                                $HCl+NaOH \to NaCl+H_{2} O$

  *  From the reaction we can observe that

      Number of moles of $NaOH$ ($n_{1}$ ) = 1

      Number of moles of $HCl$ ($n_{2}$ ) = 1

      And from the given data, Concentration of $NaOH$ ($M_{1}$ ) = 1/20 = 0.05M

      We have to find out the concentration of $HCl$ , i.e. $M_{2}$  =?

  *  If the equal volumes of $NaOH \& HCl$ are used in the reaction, i.e. $V_1=V_2$  

  *    $\frac{M_1 V_1}{n_1}= \frac{M_2 V_2}{n_2}$

     $\Rightarrow \frac{M_1}{n_1} =\frac{M_2}{n_2} ( \because V_1=V_2)$      

       $\Rightarrow \frac{0.05}{1} =\frac{M_2}{1}$

      $\therefore M_2=0.05M$

    0.05 M $HCl$ is needed to neutralize M/20 $NaOH$ solution