Question

Determine the wave length of a photon of electromagnetic radiation having energy 2.99 X 10¹² erg mol inverse ( h= 6.625X10 raise to power -34 ) ​

Answer 1

Answer : The wavelength of a photon of electromagnetic radiation is, $4.0029\times 10^{-7}m$

Explanation :

Formula used :

$E=\frac{N_A\times h\times c}{\lambda}$

where,

E = energy of photon = $2.99\times 10^{12}erg/mol=2.99\times 10^5J/mole$

conversion used : $1erg=10^{-7}J$

h = Planck's constant = $6.625\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$N_A$ = Avogadro's number = $6.022\times 10^{23}mol^{-1}$

$\lambda$ = wavelength = ?

Now put all the given values in the above formula, we get:

$2.99\times 10^5J/mole=\frac{(6.022\times 10^{23}mol^{-1})\times (6.625\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}$

$\lambda=4.0029\times 10^{-7}m$

Therefore, the wavelength of a photon of electromagnetic radiation is, $4.0029\times 10^{-7}m$