Physics, asked by shreyasjaware63, 11 hours ago

determine the wavelength of photon emitted by which has an energy of 2.5 EV

Answers

Answered by Anonymous

2

Answer:

E = hc / lambda

hc = 1240 ev nm

= > lambda = 1240 / 2.5 nm

= > lambda = 496 nm

Ans: 496 nm

Explanation:

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