determine the x component of force of magnitude 2kN force which is applied from 60 degree of x axis -
a) Fx =1.414kN
b) Fx= 1.00kN
c) Fx = 1.73kN
d) Fx = 2.414kN
Answers
Answered by
5
According to question
Given magnitude of force = F = 2 KN
We need to calculate the x component of force
Also theta = 60 deg
Thus
Fx = F * Cos theta
Fx = 2 * cos 60
cos 60 = 1/2
So
Fx = 2 /2 = 1 KN
Thus Answer is b) Fx = 1 KN
Given magnitude of force = F = 2 KN
We need to calculate the x component of force
Also theta = 60 deg
Thus
Fx = F * Cos theta
Fx = 2 * cos 60
cos 60 = 1/2
So
Fx = 2 /2 = 1 KN
Thus Answer is b) Fx = 1 KN
Answered by
2
Force F = 2kN which is applied from 60° of x - axis is shown in figure.
We know, if any vector r make an angle ∅ with x axis then, resolution of vector r is rcos∅i + rsin∅j
Means x - component of vector r is rcos∅ and y - component of vector r is rsin∅ .
Here, similarly Force F = 2kN make 60° with x - axis. Then X - component of force is Fcos60°
hence, Fx = Fcos60° = 2 × 1/2 = 1kN
Hence, option ( b) is correct
We know, if any vector r make an angle ∅ with x axis then, resolution of vector r is rcos∅i + rsin∅j
Means x - component of vector r is rcos∅ and y - component of vector r is rsin∅ .
Here, similarly Force F = 2kN make 60° with x - axis. Then X - component of force is Fcos60°
hence, Fx = Fcos60° = 2 × 1/2 = 1kN
Hence, option ( b) is correct
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