Question

Determine the zeroes of the polynomial:
2x2+ 7x -4​

Answer 1

Answer:

The two zeroes of the given equation are 1/2 and (-2).

Step-by-step explanation:

Given : p(x) = 2x^2 + 7x - 4

On comparing the given equation with the standard form of quadratic equation, we get :-

a = 2;

b = 7; and

c = (-4)

We have,

D = b^2 - 4ac

  = (7)^2 - [4(2)(-4)]

  = 49 - (-32)

  = 49 + 32

  = 81

=> D > 0

So,

x = -b ± √4ac/2a

  = -(7) ± √81/(2 x 2)

  = (-7) ± 9/4

  = (-7) + 9/4             &             (-7) - 9/4

  = 2/4             &             (-16)/4

  = 1/2             &             (-2).

I hope it helps you.

Answer 2

Answer:

The roots of the given quadratic equation are

$\boxed{\red{\sf\:x\:=\:-\:4}}\:\:\:\sf\:or\:\:\:\boxed{\red{\sf\:x\:=\:\frac{1}{2}}}$

Step-by-step-explanation:

The given quadratic equation is

2x² + 7x - 4 = 0.

2x² + 7x - 4 = 0

➞ 2x² + 8x - x - 4 = 0

➞ 2x ( x + 4 ) - 1 ( x + 4 ) = 0

➞ ( x + 4 ) ( 2x - 1 ) = 0

➞ x + 4 = 0 $\sf\:\:\:or\:\:\:$ 2x - 1 = 0

➞ x = - 4 $\sf\:\:\:or\:\:\:$ 2x = 1

$\sf\:\longrightarrow\:\boxed{\red{\sf\:x\:=\:-\:4}}\:\:\:\sf\:or\:\:\:\boxed{\red{\sf\:x\:=\:\frac{1}{2}}}$

Additional Information:

1. Quadratic Equation :

An equation having a degree '2' is called quadratic equation.

The general form of quadratic equation is

ax² + bx + c = 0

Where, a, b, c are real numbers and a ≠ 0.

2. Roots of Quadratic Equation:

The roots means nothing but the value of the variable given in the equation.

3. Methods of solving quadratic equation:

There are mainly three methods to solve or find the roots of the quadratic equation.

A) Factorization method

B) Completing square method

C) Formula method

4. Solution of Quadratic Equation by Factorization:

1. Write the given equation in the form $\sf\:{ax^{2}\:+\:bx\:+\:c\:=\:0}$

2. Find the two linear factors of the $\sf\:LHS$ of the equation.

3. Equate each of those linear factor to zero.

4. Solve each equation obtained in 3 and write the roots of the given quadratic equation.