Math, asked by bajadefrancis4, 6 months ago

Determine the zeros of quadrqtic function x²+8x-2

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Answered by kamblearun2708

Answer:

$x { }^{2} + 8x - 2 \: comparing \: \: with \: ax {}^{2} + bx - c = 0 \\ a = 1 \: \: \: b = 8 \: \: c = - 2 \\ b { }^{2} - 4ac = 1 {}^{2} - 4 \times 1 \times - 2 \\ = 1 + 8 \\ = 9$

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Determine the zeros of quadrqtic function x²+8x-2​

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Determine the zeros of quadrqtic function x²+8x-2