Math, asked by bajadefrancis4, 4 months ago

Determine the zeros of quadrqtic function x²+8x-2​

Answers

Answered by kamblearun2708
0

Answer:

x { }^{2}  + 8x - 2   \: comparing \: \: with \: ax  {}^{2}   + bx - c = 0 \\  a = 1 \:  \:  \: b = 8 \:  \: c =  - 2 \\ b { }^{2} - 4ac = 1 {}^{2}   - 4 \times 1 \times   - 2  \\   = 1  + 8 \\  = 9

Similar questions