Question

Determine the zeros of quadrqtic function x²+8x-20​

Answer 1

x2 + 10x-2x- 20

=x(x+10)-2(x-10)

=(x+10) (x-2)

Answer 2

Answer:

Let p(x) = x²+8x-20

=x²+10x-2x-20

=x(x+10)-2(x+10)

=(x+10)(x-2)

For zeroes p(x)=0

=》(x+10)(x-2)=0

=》(x+10)=0,(x-2)=0

=》x=-10 ,x=2

Hence,the zeroes are -10 and 2 .