Question

Determine theAP whose. Third some is16 and7term exceeds the 5th term by 12

Answer 1

Answer:

a3 =16 , a7 = a5 + 12

let a , d be the first term and common difference of an A.P

a3 = a + 2d

16 = a + 2×6

16= a + 12

16 -12 = a

a = 4

a7 = a5 + 12

a + 6d = a + 4d + 12

cancel a with a

6d - 4d = 12

2d = 12

d =6

A.P are

a ,a+d ,a+2d

4, 4+6 , 4 +2×6

4 , 10 , 16

Answer 2

Answer:

a3 = 16, a7 = a5 + 12

a7= a5 + 12

a + 6d= a + 4d +12

6d - 4d = 12

2d = 12

d = 12/2

d = 6

a3 =16

a + 2d = 16

a + 2×6 = 16

a + 12 =16

a = 16-12

a = 4

a1 = 4 , a2= 4+6 = 10, a3 = 16, a4 = 16+6= 22

AP = 4,10,16,22 ....