determine thr greatest digit divisible by 6,8,12
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When we multiply 24 with 2, 3, 4 we get only 2 digits. Therefore multiply 24 with 5. Now we get the three digit number 120. Therefore 120 is the smallest three digit number divisible by 6, 8 and 12.
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Here is your answer:-
Greatest number divisible by 6,8,12 is = to their HCF
Factors of 6:- 1,2,3,6
Factors of 8:- 1,2,4,8
Factors of 12:- 1,2,3,4,12
Largest common factor of 6,8 and 12= 2
Ans:- The greatest digit divisible by 6,8 and 12 is 2.
Hope it helps :D
-> Minecraftshreyas
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