Question

determine total number of electrons present in p- subshell of 'Zn'?​

Answer 1

Answer:

electronic configuration of Zn is 1s

2

2s

2

2p

6

3s

2

3p

6

3d

1

04s

2

Case 1:n=4,l=0,m=0 means [4s] which have 2 electrons.

Case 2:n=3,l=1,m=0 means [3p] which have 6 electrons.

Case 3:n=2,l=1,m=1 means [2p] which have 6 electrons.

So total number of electron having [n+l+m=4] is 2+6+6=14