determine total resistance of the circuit given in photo please it is urgent
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hello friend..!!
to determine the total resistance in the circuit ,
when ' i ' current flows from the positive terminal of the battery through the 5 Ω resistance , the current splits into ' i1 ' and ' i - i1 ' respectively , implies that ,
3Ω and 7Ω are in series so therefore R = R1 + R2
R = 3 + 7 = 10Ω------------------------(1)
this 10Ω resistance is parallel to the given 10Ω resistance in the circuit ,
therefore the total resistance is, 1/ R1 + 1/R2
1/R = 1/ 10 + 1/10 = 2/10 implies R = 10/2 = 5Ω------------------------(2)
now, in the given diagram the total resitance in thr small upper triangle is 5Ω.
now, to find the total resistance in the whole circuit ,
the all three 5Ω are in series so therefore,
R = R1 + R2 + R3
R = 5Ω + 5Ω + 5Ω = 15Ω.
SO , therefore 15Ω is the total resistance in the circuit .
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hope it is useful..!!
to determine the total resistance in the circuit ,
when ' i ' current flows from the positive terminal of the battery through the 5 Ω resistance , the current splits into ' i1 ' and ' i - i1 ' respectively , implies that ,
3Ω and 7Ω are in series so therefore R = R1 + R2
R = 3 + 7 = 10Ω------------------------(1)
this 10Ω resistance is parallel to the given 10Ω resistance in the circuit ,
therefore the total resistance is, 1/ R1 + 1/R2
1/R = 1/ 10 + 1/10 = 2/10 implies R = 10/2 = 5Ω------------------------(2)
now, in the given diagram the total resitance in thr small upper triangle is 5Ω.
now, to find the total resistance in the whole circuit ,
the all three 5Ω are in series so therefore,
R = R1 + R2 + R3
R = 5Ω + 5Ω + 5Ω = 15Ω.
SO , therefore 15Ω is the total resistance in the circuit .
-------------------------------------------
hope it is useful..!!
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