Question

Determine two consecutive even positive integer's the sum of whose squares is 100

Answer 1

Answer:

Step-by-step explanation:

let the two integers be n,n+2

n^2+(n+2)^2=100

n^2+n^2+4n+4=100

2n^2+4n-96=0

192=2*96=2*2*48=2*2*6*8=2*2*2*3*2*2*2

2n^2+16n-12n-96=0

2n(n+8)-12(n+8)=0

n=6,-4

the numbers be 6,8