determine two positive number whose sum is 15 and sum of whose squares in minimum
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Step-by-step explanation:
Let the first number is x,
Since, the sum of two number is 15,
⇒ First number + second number = 15,
⇒ x + second number = 15
⇒ Second number = 15 - x
Let f(x) shows the sum of the squares of the number,
⇒ f(x) = x² + (15-x)² = 2x²- 30x + 225,
By differentiating with respect to x,
We get,
f'(x) = 4x - 30,
For maximum or minimum, f'(x) = 0,
⇒ 4x - 30 = 0 ⇒ x = 7.5,
Again differentiating f'(x) with respect to x,
f''(x) = 4
At x = 7.5 f''(x) = Positive,
Thus, f(x) is minimum at x = 7.5,
Hence, the first number is 7.5,
And, the second number is 15 - 7.5 = 7.5
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