Question

determine value of k for which (k²+4k+8),(2k²+3k+6) and (3k²+4k+4) are in a.p​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

k=0

Step-by-step explanation:

(k²+4k+8),(2k²+3k+6) and (3k²+4k+4) are in a.p

So 2(2k²+3k+6)=k²+4k+8+3k²+4k+4

4k²+6k+12=4k²+8k+12

2k=0

k=0