determine van't hoff factor for a tribasic acid H3A assuming first dissociation as 100% second dissociation 50% and third dissociation as 20%
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The value of vantt hoff factor is 0.4
Given that:
- H3A is a tribasic acid.
- The first dissociation of the acid = 100%
- The second dissociation of the acid = 50%
- The third dissociation of the acid = 25%
Solution:
H3A ------------> H+(1) + H2A-(1)
H2A- (1 -0.5) ------------> H+ (0.5) + HA-2 (0.5)
HA-2 (0.5 - 0.5 [0.2]) -----------> H+ (0.1) + A-3 (0.1)
Now calculate the value of van't hoff factor
van't hoff factor (i) = (1 + 0.5 + 0.1 + 0.5 + 0.4 + 0.1)
van't hoff factor = 0.4
Thus, the value of vantt hoff factor is 0.4
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