Question

determine volumetrically the molarity of Hcl solution with the help of M/20 naoh solution supplied​

Answer 1

The question is incomplete, complete question is:

Determine volumetrically the molarity of HCl solution with the help of M/20 NaOH solution supplied​, where volume of NaOH used is 100 mL and HCL is 50 mL.

The molarity of the HCl solution is 10 M.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=50 mL\\n_2=1\\M_2=\frac{1}{20}M\\V_2=100 mL$

Putting values in above equation, we get:

$1\times M_1\times 50 mL=1\times \frac{1}{20} M\times 100 mL$

$M_1=10 M$

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