Question

Determine weather the value given
aquinot each of Quadratic equation
ame roots of equation.2x²-7x+6=0,x=-2,3/2​

Answer 1

Step-by-step explanation:

mrudulyathisha6

Helping Hand

1 answer

1 people helped

Answer:

2*(1.5)^2-7*(1.5)+6

=2*2.25-10.5+6

=0

Step-by-step explanation:

substitute 1.5 in place of x and if it is equal to zero thats ur ans

bye

Answer 2

$\large\bf\underline\red{Given \: :- }$

• 2x²-7x+6=0
• x=2 and 3/2

$\large\bf\underline\red{To \: find \: :- }$

• Determine the values are the roots of quadratic equation.

$\large\bf\underline\red{Solution \: :- }$

Given that,

x = 2 and 3/2

First checking x = 2 is the root of 2x² - 7x + 6 = 0.

Put the value in equation

$⟼ \: \sf{2(2) {}^{2} - 7(2) + 6 = 0 } \\⟼ \: \sf{2(4) - 14 + 6 = 0 } \: \: \: \: \: \\ ⟼ \: \sf{8 - 14 + 6 = 0} \: \: \: \: \: \: \: \: \: \: \: \\⟼ \: \sf{8 + 6 = 14} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ ⟼\sf{8 = 14 - 6 = 8} \: \: \: \: \: \: \: \: \: \:$

$⟼\sf\pink{8 = 8}$

After determining,

x = 2 is the root of 2x² - 7x + 6 = 0

Checking x = 3/2 is the root 2x² - 7x + 6 = 0

$⟼\sf{2( \frac{3}{2} ) {}^{2} - 7( \frac{3}{2}) + 6 = 0 } \\ ⟼\sf{2 \times \frac{9}{4} - \frac{21}{2} + 6 = 0 } \: \: \: \\ ⟼\sf{ \frac{18}{4} - \frac{21}{2} + 6 = 0} \: \: \: \: \: \: \: \: \\ ⟼\sf{ \frac{9}{2} - \frac{21}{2} + 6 = 0 } \: \: \: \: \: \: \: \: \: \: \\ ⟼\sf{ \frac{9 - 21}{2} + 6 = 0 } \: \: \: \: \: \: \: \: \: \: \: \\ ⟼\sf{ \frac{ - 12}{2} + 6 = 0 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ ⟼\sf{ - 6 + 6 = 0 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$⟼\sf\pink{6 = 6}$

After determining,

x = 3/2 is the root of 2x² - 7x + 6 = 0

x = 2 and 3/2 are the real roots.

_______________________________