Question

determine whether a number is a perfect number an armstrong number or a palindrome in python

Answer 1

added a txt file as brainly found text it innapropriate. open and paste the text in python

e9b2c66814af11af9f6aeb2e901e7642.txt

Answer 2

Answer:

The below python code checks whether a number is a perfect number an Armstrong number or a palindrome:

def perfect_number(n):

  summ=0

  for i in range(1,n):

    if(n%i==0):

      summ+=i

if(summ==n):

  return("Number is perfect number")

else:

 return("Number is not a perfect number")

def armstrong(n):

  num = str(n)

 length = len(num)

 for i in range(1,length):

  s += num[i]**length

if(s==n):

return("Number is Armstrong number")

else:

return("Number is not Armstrong number")

def palindrome(n):

num1 = str(n)

if(num1==num1[::-1]):

return ("Number is a palindrome")

else:

 return("Number is not palindrome")

#DRIVER CODE

number = int(input())

print(perfect_number(number))

print(armstrong(number))

print(palindrome(number))

Explanation:

PERFECT NUMBER

A number is said to be a perfect number if the sum of its positive divisors (excluding the number) is equal to the number.

For example:

6 is the perfect number because its divisors sum 1+2+3 =6

ARMSTRONG NUMBER

A number is an Armstrong number if the sum of its digits with the power of length or order of the number is equal to the number.

For example:

153 is an Armstrong number. Because the order of the number is 3

and 1x1x1 + 5x5x5 + 3x3x3 = 153

PALINDROME NUMBER

A number or string is a palindrome if the reverse of the number is equal to the original number.

For example:

121 is a palindrome number. Because its reverse is also 121.

In the above code, I just mapped these properties with the respective functions and checked the number that comes in which categroty.

#SPJ3