Math, asked by Troy2159, 9 months ago

Determine whether (i) x= √2, (ii) x = –2√2 are the solutions of the equation x2 + √2 x – 4 = 0 or not.

Answers

Answered by Anonymous
24

Question:

Determine whether x=√2 and x=-2√2 are the solutions of the equation x² + √2x - 4 = 0 or not.

Answer:

x = √2 and x = -2√2 are the solutions of the given equation.

Note:

• The possible values of unknown (variable) for which the equation is satisfied are called its solutions or roots .

• If x = a is a solution of any equation in x , then it must satisfy the given equation otherwise it's not a solution (root) of the equation.

Solution:

The given equation is : x² + √2x - 4 = 0 ------(1)

Let's check whether x = √2 is a solution of eq-(1) or not .

Putting x = √2 in eq-(1) , we have ;

=> (√2)² + √2•√2 - 4 = 0

=> 2 + 2 - 4 = 0

=> 0 = 0 (which is true)

Since , eq-(1) is satisfied by x = √2 , thus x = √2 is a solution of eq-(1) .

Now,

Let's check whether x = -2√2 is a solution of eq-(1) or not .

Putting x = -2√2 in eq-(1) , we have ;

=> (-2√2)² + √2•(-2√2) - 4 = 0

=> 8 - 4 - 4 = 0

=> 0 = 0 (which is true)

Since , eq-(1) is satisfied by x = -2√2 ,

Thus x = -2√2 is a solution of eq-(1).

Answered by Anonymous
25

\huge{\boxed{\red{Answer}}}

\large{\underline{\pink{Required\;to\;find}}}

Whether\;\sqrt{2}\;and\;-2\sqrt{2}\;are\;roots\;of\;equation\\  x^{2}+\sqrt{2}x-4=0

\large{\underline{\pink{Verifying\;\sqrt{2}\;as\;a\;root}}}

  • Substituting \sqrt{3} in the equation
  • x^{2}+\sqrt{2}x+6=0
  • {(\sqrt{2})}^{2}+\sqrt{2}(\sqrt{2})-4=0
  • 2+2-4=0
  • 0=0

\boxed{\green{Therefore\;\sqrt{2}\;is\;a\;root}}

\large{\underline{\pink{Verifying\;-2\sqrt{2}\;as\;a\;root}}}

  • Substituting -2\sqrt{2} in the equation
  • x^{2}+\sqrt{2}x-4=0
  • {(-2\sqrt{2})}^{2}+\sqrt{2}(-2\sqrt{2})-4=0
  • 8-4-4=0
  • 0=0

\boxed{\green{Therefore\;-2\sqrt{2}\;is\;a\;root}}

\boxed{\red{Therefore\;\sqrt{2}\;and\;-2\sqrt{2}\;are\;roots\;of\;given\;equation}}

\huge{\boxed{\blue{NOTE}}}

  • If 'a' is a root of a given equation then it must satisfy the given equation
  • I have used the above statement to verify -3 as root of given equation
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