Determine whether (i) x= √2, (ii) x = –2√2 are the solutions of the equation x2 + √2 x – 4 = 0 or not.
Answers
Question:
Determine whether x=√2 and x=-2√2 are the solutions of the equation x² + √2x - 4 = 0 or not.
Answer:
x = √2 and x = -2√2 are the solutions of the given equation.
Note:
• The possible values of unknown (variable) for which the equation is satisfied are called its solutions or roots .
• If x = a is a solution of any equation in x , then it must satisfy the given equation otherwise it's not a solution (root) of the equation.
Solution:
The given equation is : x² + √2x - 4 = 0 ------(1)
Let's check whether x = √2 is a solution of eq-(1) or not .
Putting x = √2 in eq-(1) , we have ;
=> (√2)² + √2•√2 - 4 = 0
=> 2 + 2 - 4 = 0
=> 0 = 0 (which is true)
Since , eq-(1) is satisfied by x = √2 , thus x = √2 is a solution of eq-(1) .
Now,
Let's check whether x = -2√2 is a solution of eq-(1) or not .
Putting x = -2√2 in eq-(1) , we have ;
=> (-2√2)² + √2•(-2√2) - 4 = 0
=> 8 - 4 - 4 = 0
=> 0 = 0 (which is true)
Since , eq-(1) is satisfied by x = -2√2 ,
Thus x = -2√2 is a solution of eq-(1).
- Substituting in the equation
- 0=0
- Substituting in the equation
- 8-4-4=0
- 0=0
- If 'a' is a root of a given equation then it must satisfy the given equation
- I have used the above statement to verify -3 as root of given equation