Math, asked by shubail, 11 months ago

determine whether minus 2 root 3 is a solution of the quadratic equation X square minus 3 root 3 X + 6=0


fazailcheema: complete question pls
shubail: it is completed
fazailcheema: ok
ankitagni: by putting x = -2√3 the value is not zero so it is not a solution
SumitJi: yes

Answers

Answered by SumitJi
2
Here is your answer Dear!!
Attachments:
Answered by fazailcheema
1

Answer:

hey buddy,

It is not the root of the given equation.

Step-by-step explanation:

Since the quadratic equation that is given here is

x²- 3√3x + 6=0

If the roots are correct then they should satisfy the given equation:

The root that is given here is = -2√3= -3.464

So, if we need to find out that if this is the root of the given equation then we need to put that root in the above equation.

(-2\sqrt{3})^{2}  -3\sqrt{3(-2\sqrt{3}) } +6=0

0r use the Quadratic Formula:

x=\frac{-b±\sqrt{b^{2} -4ac} }{2a}

Here I am using Quadratic formula to find the roots,

The roots are= 2√3 or 1.73

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