Question

Determine whether the following quadratic equation
has real roots or not. x^ - x -2=0
​

Answer 1

${x}^{2} - x - 2 = 0 \\ {b}^{2} - 4ac = 0 \\ {1}^{2} - 4 \times - 2 \times 1 \\ 1 + 8 = 9$

since the discriminant is greater than zero it has real roots.

Answer 2

$\huge \bold{hello \: mate}$

=>x²-x-2=0

Here, a=1,b=-1, c=-2

Now,

b²-4ac=√D

(-1)²-4(1)(-2)=√D

1+8=√D

√D=9

D=+9

Hence, the equation will have real and distinct roots.