Math, asked by rohitchouhan8568, 6 months ago

Determine whether the function f(x)=x+1 from the set of real number to itself is one to one​

Answers

Answered by crystal35
1

Let the number of appearing students be 100.

Pass only in 0 topic – 10

1 – 16 (20% of 80)

2 – 20 (25% of 80)

3 – 20% (100 – (16+20+24+20))

4 – 24%

5 – 20%

Therefore, 20% of x = 500 => x = 2500

The question is " If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination?"

The total number of students is 2500.

Hence, the answer is 2500.

HOPE it helps you and mark me as a braienlist and follow me

Answered by pulakmath007
1

SOLUTION

TO DETERMINE

Whether the function f(x) = x + 1 from the set of real number to itself is one to one

EVALUATION

Here the given f : R → R is defined by

f(x) = x + 1

Let x₁ , x₂ ∈ R be such that

 \sf f(x_1) = f(x_2)

 \sf \implies x_1 + 1 = x_2 + 1

 \sf \implies x_1  = x_2

Thus we have

 \sf f(x_1) = f(x_2) \:  \: implies \:  \: x_1 = x_2

Thus f is one to one

FINAL ANSWER

f is one to one

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. if given f(x) = 6(1 - x), what is the value of f(-8)?

https://brainly.in/question/22543444

2. let f and g be thwe function from the set of integers to itself defined by f(X) =2x +1 and g (X)=3x+4 then the compositi...

https://brainly.in/question/22185565

Similar questions