Question

Determine whether the given is a rational function, a rational equation, a rational inequality or none of these.#paHelpNaman

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Answer 1

Answer:

3x^2y+2x^3-y^3+5xy^2

Step-by-step explanation:

3x^2y+2x^3-y^3+5xy^23x^3x^2y+2x^3-y^3+5xy^2+2x^3-y^3+5xy^2

Answer 2

Step-by-step explanation:

Given:

$1. \frac{1 + x}{x - 2} = 4$

$2.5x \geqslant \frac{2}{2x - 1}$

$3.f(x) = \frac{ {x}^{2} - 7 }{x + 2} - 3$

$4. \frac{x + 2}{x - 2} = y + 3$

$5. \frac{x + 1}{2} < \sqrt{x + 2}$

To find: Determine whether the given is a rational function, a rational equation, a rational inequality or none of these.

Solution:

1. $\frac{1 + x}{x - 2} = 4$

It is a rational equation.

Rational equations are in the form p/q=c,here p and q are polynomial and c can be a constant or a polynomial.

2.$5x \geqslant \frac{2}{2x - 1}$

It is a rational inequation.

Rational inequations are in the form p/q (sign of inequality )c,here p and q are polynomial and c can be a constant or a polynomial.

3. $f(x) = \frac{ {x}^{2} - 7 }{x + 2} - 3$

It is a rational function.

Rational functions are in the form f(x)=p/q ±c,here p and q are polynomial and c can be a constant or a polynomial.

4.$\frac{x + 2}{x - 2} = y + 3$

It is a rational function.

It can be expressed as

$y = \frac{x + 2}{x - 2} - 3$

here, we know that y =f(x)

Rational functions are in the form f(x)=p/q ±c,here p and q are polynomial and c can be a constant or a polynomial.

5.$\frac{x + 1}{2} < \sqrt{x + 2}$

It is none of these.

Because it doesn't follow any of the criteria.

Hope it helps you.

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