Question

Determine whether the given numbers are solutions of the given equation or not x² – 3√3x + 6 = 0; √3, – 2√3

Answer 1

Answer:

Step-by-step explanation:

x^2-3root3x+6=0

=>(x=root3) => (root3)^2 -3root3*root3+6 =0

=>3-3root3^2 +6 =0

=> 3-3-+6=0

=>0+6=0

=>6=0

(x= -2root3)

=> (-2root3)^2-3root * -2root3+6=0

=>4*3