Question

Determine whether the given quadratic equation has root(s). If so, find the
root(s): z2 - 6z + 4 = 0.​

Answer 1

Answer:

Yes

Step-by-step explanation:

z^2-6z+4=0

To find the root use the quadratic equation,z={-b+√(b^2-4ac)}/2a and {-b-√(b^2-4ac)}/2a

Now

a=1

b=-6

c=4

√[b^2-4ac]=√[(-6)^2-4×1×4] =√ [36-16]=√20

Now we get a positive number.There are two roots.

If it is 0 then 1 root and if it is a negative number then no roots exist.

Now,

z=6+_(√20)/2 = 3+_√20

Here +_ indicates plus or minus.

The required roots are 3+√20=z

and 3-√20=z.