Question

Determine whether the given quadratic equation has roots 3y^2 + (6+4a)y+8a = 0

Answer 1

Answer:

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Step-by-step explanation:

mugsswmsyhkfgdjtegiigfutajfgoigtsahlhystsdu

Answer 2

Answer:3Y^ 2+{6+4A}Y+8a= answer is down

Step-by-step explanation:

3y^2+(6)y =-8a /4a

3y^2+6y+(8/2)^2 = -8/4+(8/2)^2

now (8/2)^2 is added on both sides

(3y+8/2)^2 = -8/4+8/4 =( 3y+ 8/2) ^2 = 0

x= -8/2 or x=8/2