Question

Determine whether the given quadratic equation has roots). If so, find the root(s): 5y2 - 2y - 2 = 0.​

Answer 1

5y²-2y-2=0

here a = 5 ,b = -2 c = -2

so, D = b²-4ac

$\implies$ (-2)²-4×5×(-2)

$\implies$ 4-(-40)

$\implies$ 4+40

$\implies$ 44

Here D > 0

hece, this equation has real and distinct roots.

By quadratic formula

$\alpha$ = b+√D/2a

$\alpha$ = -2+√44/10....ans......

and,

$\beta$ = -2-√44/10