Determine whether the given set of points in each case are collinear or not. (i) (7, -2), (5, 1), (3, 4)
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Answered by
1
Step-by-step explanation:
Hi Friend,
Given: A(7,-2), B(5,1), C(3,4)
To prove: The given points are collinear.
We know that, if Area of triangle = 0, then the points are collinear.
{(x1y2 + x2y3 + x3y1) - (y1x2 + y2x3 + y3x1)} = 0
{[7(1) + 5(4) + 3(-2)] - [-2(5) + 1(3) + 4(7)]} = 0
{[7+20-6] - [-10+3+28]} = 0
(21 - 21) = 0
0 = 0
Since the given points are collinear.
Answered by
1
Answer:
0=0
Step-by-step explanation:
Hi Friend,
Given: A(7,-2), B(5,1), C(3,4)
To prove: The given points are collinear.
We know that, if Area of triangle = 0, then the points are collinear.
{(x1y2 + x2y3 + x3y1) - (y1x2 + y2x3 + y3x1)} = 0
{[7(1) + 5(4) + 3(-2)] - [-2(5) + 1(3) + 4(7)]} = 0
{[7+20-6] - [-10+3+28]} = 0
(21 - 21) = 0
0 = 0
Since the given points are collinear.
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