Determine whether the given values are solutions of the given equations or not..
Kindly help....
Attachments:
Answers
Answered by
2
a²x² -3abx +2b² = 0
a²x² -2abx -abx +2b² = 0
ax(ax -2b) - b( ax - 2b) = 0
( ax - b) ( ax - 2b) =0
x = b/a , 2b/a
hence, x = b/a possible
but x ≠ a/b
a²x² -2abx -abx +2b² = 0
ax(ax -2b) - b( ax - 2b) = 0
( ax - b) ( ax - 2b) =0
x = b/a , 2b/a
hence, x = b/a possible
but x ≠ a/b
Similar questions