Math, asked by harrysingh12576, 9 months ago

Determine whether the given values are solutions of the given equation

or not

1)x²–3√3+6=0,x=√3,x=–2√3

2)x²–√2x–4=0 ,.x=–√2,x=–2√2

3)a²x²–3abx+2b²=0,x=a/b,x=b/a​

Answers

Answered by sparsh2412
0

Step-by-step explanation:

1).

no both

2).bothyes

3).

both no!!

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