Question

determine whether the given values of x are zeros of polynomial or not 9x^2 -3x -2 , x = -1 / 3 , x = 2/ 3​

Answer 1

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Answer 2

$\huge \mathfrak \red{Answer}$

Let p(x) = 9x2 - 3x - 2

Put x = -1/3

${ \bf⇒p(-1/3)} \\ </p><p> \implies 9(-1/3)2 -3(-1/3) -2 \\ </p><p> \implies1+1 - 2 \\ </p><p> \boxed {\implies0 }</p><p>$

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Put x = 2/3

$\bf{⇒ p(2/3) } \\ \implies</p><p>9x2 - 3x - 2 \\ \implies</p><p> 9(2/3)2 -3(2/3) - 2 \\ \implies</p><p>= 4 - 2 - 2 \\ \boxed {\implies</p><p>= 0}</p><p>$

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Therefore the given value of x is a zero of the given polynomial.

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