determine whether the point (0,0),(2,1),(4,3),(2,-6),(0,-1) lie inside outside or on the circle x²+y²-5x+2y-5=0
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Answer:
The equation of the given circle is x
2
+y
2
=25
⇒ Centre =(0,0) and radius =5
Distance between point (−2.5,3.5) and centre (0,0)
=
(−2.5−0)
2
+(3.5−0)
2
=
6.25+12.25
=
18.5
=4.3(approx)<5
Since the distance between point (−2.5,3.5) and centre (0,0) of the circle is less than the radius of the circle.
Hence the point (−2.5,3.5) lies inside the circle.
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