Determine whether the points A( 1, 2) , B( 5, 3), C(8, 6) are collinear.
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Answer:
Given points are A(3,1),B(6,4) and C(8,6).
If AB+BC=AC, then the three points are collinear.
By distance formula, AB =
[(x
2
−x
1
)
2
+(y
2
−y
1
)
2
]
AB =
[(6−3)
2
+(4−1)
2
]
AB =
[(3)
2
+(3)
2
]
AB =
[9+9]
AB =
18
AB =
(9×2)
AB = 3
2
By distance formula, BC =
[(x
2
−x
1
)
2
+(y
2
−y
1
)
2
]
BC =
[(8−6)
2
+(6−4)
2
]
BC =
[(2)
2
+(2)
2
]
BC =
[4+4]
BC =
8
BC =
(4×2)
BC = 2
2
By distance formula, AC =
[(x
2
−x
1
)
2
+(y
2
−y
1
)
2
]
AC =
[(8−3)
2
+(6−1)
2
]
AC =
[(5)
2
+(5)
2
]
AC =
[25+25]
AC =
50
AC =
(25×2)
AC = 5
2
AB+BC = 3
2
+2
2
=5
2
= AC
Hence proved.
So A,B,C are collinear.
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