Question

Determine whether the signal is power or energy

Answer 1

i) x(t)=0.9e−3tu(t)x(t)=0.9e−3tu(t)

E=∫−∞∞|x(t)|2dtE=∫−∞∞|x(t)|2dt

=∫−∞∞|0.9e−3tu(t)|2dt=0.81∫0∞e−6tdt=0.81[e−6t−6]∞0=0.81/6E=0.135J=∫−∞∞|0.9e−3tu(t)|2dt=0.81∫0∞e−6tdt=0.81[e−6t−6]0∞=0.81/6E=0.135J

Since the signal is not periodic hence it’s not a power signal but it is a energy signal.

(ii) x[n]=u[n]x[n]=u[n]

The signal is periodic because u(n) repeats after every sample and of infinite duration.

Hence it is a Power Signal
in above picture

Answer 2

Answer:

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