Question

determine whether the value given against each of the quadratic equations are the root fo quadratic equations or not . 1)x²+5x-6=0;x=-6,2​

Answer 1

Answer:

Step-by-step explanation:

Factorise x^2+5x-6

x^2+6x-x-6

x(x+6)-1(x+6)

(x-1)(x+6)

Put values of 2 and -6 in place of x

-6 will give 0 so it is a root.

2 won't give 0 so it is not a root.

Answer 2

Answer:

2 is not the root of the equation

-6 is a root of the equation

Step-by-step explanation:

Factorise the given equation:

$x^2 + 5x - 6 \\x^2 + 6x - x - 6 \\ x^2 - x + 6x - 6 \\ x(x - 1) + 6(x - 1) \\ (x + 6)(x - 1)$

From here we can see that the two values of x are

(x+6) = 0

x = -6

and the second root is

(x-1) = 0

x = 1

From this we can conclude that 2 is not the zero of this equation and -6 is a zero of the equation.