determine whether the value given agaisnt the quadratic equation are the roots of the equation
2x1+9x+10=0 , x= -3, -5/2
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→ refer to attachment now, [tex]p( \frac{5}{2} ) = 2( \frac{5}{2} ) ^{2} - 5( \frac{5}{2} ) = 0 \ \ = 2( \frac{25}{4} ) - \frac{25}{2} = 0 \ \ = \frac{25}{2} ...
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Assume the integer be x. Then its square will be x2. And given, their sum is 90 ⇒ x + x2 = 90 ⇒ x2 + x – 90 = 0 Solving for x by factorization method, we have x2 + 10x – 9x – 90 = 0 ⇒ x(x + 10) – 9(x + 10) = 0 ⇒ (x + 10)(x – 9) = 0 Now, either x + 10 = 0 ⇒ x = –10 Or, x – 9 = 0 ⇒ x = 9 .
Thus, the values of the integer are 9 and -10 respectively.
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